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4x+2.67x^2=72
We move all terms to the left:
4x+2.67x^2-(72)=0
a = 2.67; b = 4; c = -72;
Δ = b2-4ac
Δ = 42-4·2.67·(-72)
Δ = 784.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{784.96}}{2*2.67}=\frac{-4-\sqrt{784.96}}{5.34} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{784.96}}{2*2.67}=\frac{-4+\sqrt{784.96}}{5.34} $
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